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Given that there are three spotted Pacific banana slugs for every four non spotted Pacific banana slug(s) in Arcata's community forest, let xx represent the probability of drawing a single spotted Pacific banana slug from a single draw of both varieties of spotted and non spotted slugs.

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Answer:

The probability of selecting a single spotted Pacific banana slug will be [tex]\frac{3}{7}[/tex].

Step-by-step explanation:

There are three spotted Pacific banana slugs for every four non spotted Pacific banana slugs.

There are three  spotted Pacific banana slugs in every group of 7 Pacific banana slugs.

There are four non spotted Pacific banana slugs in every group of 7 Pacific banana slugs.

Therefore the probability of selecting a single spotted Pacific banana slug will be

[tex]\frac{number \hspace{0.1cm} of \hspace{0.1cm} spotted \hspace{0.1cm} Pacific \hspace{0.1cm} banana \hspace{0.1cm} slugs \hspace{0.1cm} in \hspace{0.1cm} group \hspace{0.1cm} of \hspace{0.1cm} 7 \hspace{0.1cm} Pacific \hspace{0.1cm} banana \hspace{0.1cm} slugs}{number \hspace{0.1cm} of \hspace{0.1cm} slugs \hspace{0.1cm} in \hspace{0.1cm} a \hspace{0.1cm} group \hspace{0.1cm} of \hspace{0.1cm} 7 \hspace{0.1cm} Pacific \hspace{0.1cm} banana \hspace{0.1cm} slugs}[/tex] = [tex]\frac{3}{7}[/tex].

The probability of selecting a single non spotted Pacific banana slug will be = [tex]\frac{4}{7}[/tex].

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