140 grams of NaNO3 was dissolved in 100 grams of water at 80 degrees Celsius. The solution is_______________.


unsaturated

saturated

supersaturated

Respuesta :

Answer:

This solutions is unsaturated

Explanation:

Step 1: Data given

MAss of NaNO3 = 140 grams

MAss of water = 100 grams

Temperature water = 80.0°C

Saturated Solution = A solution with solute that dissolves until it is unable to dissolve anymore.

Unsaturated Solution = A solution (with less solute than the saturated solution) that completely dissolves.

Supersaturated Solution = A solution (with more solute than the saturated solution) that contains more undissolved solute than the saturated solution because of its tendency to crystallize and precipitate

Step 2

A NaNO3solution is saturated at a temperature of 80.0 °C when 148 grams of NaNO3 is dissolved per 100 mL water ( 100 grams water).

140 grams < 148 grams

This solutions is unsaturated

Answer:

unsaturated

Explanation: