To solve this problem we will apply the concepts related to energy conservation. For this purpose we know that heat would be equivalent to the change in work and the internal energy of the system. Mathematically,
[tex]Q = W + \Delta U[/tex]
Here,
Q = Heat Flow
W = Work
[tex]\Delta U = nC_v \Delta T[/tex] Here,[tex]\Rightarrow n = \text{Number of moles}, C_v = \text{Specific heat}, \Delta T = \text{Change in temperature}[/tex]
Considering that the specific heat for the monatomic gas is [tex]3/2*8.314J/mole[/tex], we have,
[tex]Q = 580J + (\frac{3}{2} (4 moles)(8.314J/mole)(110))[/tex]
[tex]Q = 4907.24J[/tex]
Therefore the heat flows into or out of the gas is 4907.24J