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Factor completely 2x4y3 − 12x3y2 − 8x2y.

2x2y(x2y2 − 6xy − 4)
2(x4y3 − 6x3y2 − 4x2y)
2y(x4y2 − 6x3y − 4x2)
Prime

Respuesta :

calculista

Answer:

[tex]2x^2y[x^{2}y^{2}-6xy-4][/tex]

Step-by-step explanation:

we have

[tex]2x^{4}y^{3}-12x^3y^2-8x^2y[/tex]

Factor [tex]2x^2y[/tex]

so

[tex]2x^2y[x^{2}y^{2}-6xy-4][/tex]

Answer:

Question: Factor completely 2x4y3 − 12x3y2 − 8x2y.

Possible Answer: A. 2x2y(x2y2 − 6xy − 4)

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