Respuesta :
Answer:
The rate of concentration is 1.87 mol L⁻¹s⁻¹
Explanation:
First order reaction: First order reaction is only depends on the value of the concentration of only one reactant.
A(g)+B(g)⇒AB(g)
rate of reaction = k [A][B] [ since A and B are first order reaction]
k= rate constant
[A] = concentration of A
[B] = concentration of B
Given that rate = 0.625 mol/L.s
[A] = 2 mol/L and [B] = 2 mol/L
Therefore,
rate of reaction = k [A][B]
⇒0.625= k ×2×2
[tex]\Rightarrow k=\frac{0.625}{4} mol^{-2}L^2 s^{-1}[/tex]
The value of k changes only when the temperature changes.
Now [A]= 4.41 mol/L and [B]= 2.72 mol/L
Rate of reaction = K[A][B]
[tex]\Rightarrow \textrm {Rate of reaction} = \frac{0.625}{4} \times 4.41 \times 2.72[/tex]
[tex]\Rightarrow \textrm {Rate of reaction} = 1.874[/tex] ≈1.87 mol L⁻¹s⁻¹
The rate of concentration is 1.87 mol L⁻¹s⁻¹
