Answer: The mass of HCN that could be made is 6.183 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of ammonia = 5.90 g
Molar mass of ammonia = 17 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ammonia}=\frac{5.90g}{17g/mol}=0.347mol[/tex]
Given mass of oxygen gas = 11.0 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{11.0g}{32g/mol}=0.344mol[/tex]
Given mass of methane = 4.67 g
Molar mass of methane = 16 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of methane}=\frac{4.67g}{16g/mol}=0.292mol[/tex]
For the given chemical reaction:
[tex]2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)[/tex]
The mole ratio of the reactants are:
[tex]NH_3:O_2:CH_4=2:3:2::1:1.5:1[/tex]
As, the moles of oxygen gas is the lowest. So, it is considered as the limiting reagent
By Stoichiometry of the reaction:
3 moles of oxygen gas produces 2 moles of HCN
So, 0.344 moles of oxygen gas will produce = [tex]\frac{2}{3}\times 0.344=0.229mol[/tex] of HCN
Now, calculating the mass of HCN from equation 1, we get:
Molar mass of HCN = 27 g/mol
Moles of HCN = 0.229 moles
Putting values in equation 1, we get:
[tex]0.229mol=\frac{\text{Mass of HCN}}{27g/mol}\\\\\text{Mass of HCN}=(0.229mol\times 27g/mol)=6.183g[/tex]
Hence, the mass of HCN that could be made is 6.183 grams