Answer:
The magnitude of car A acceleration is 4 times that of car E
Explanation:
Assuming they are traveling at a constant speed. Their (centripetal) acceleration is as the following
[tex]a = \frac{v^2}{r}[/tex]
where v is the (linear) velocity and r is the radius. We can use this to calculate their ratio
[tex]a_A / a_E = \frac{v_A^2/r_A}{v_E^2/r_E} = \left(\frac{v_A}{v_E}\right)^2\frac{r_E}{e_A}[/tex]
Since [tex]v_A = 2V_E \rightarrow \frac{v_A}{v_E} = 2[/tex] and [tex]r_A = r_E[/tex]
[tex]a_A / a_E = 2^2 = 4[/tex]
So the magnitude of car A acceleration is 4 times that of car E
