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consider the following elementary reaction:
N2O—> N2 + O
suppose we let K1 stand for the rate constant of this reaction, and k-1 stand for the rate constant of the reverse reaction. write an expression that gives the equilibrium concentration of N2O in terms of k1, k-1 and the equilibrium concentrations of N2 and O

Respuesta :

Answer : The expression that gives the equilibrium concentration of N₂O in terms of K₁, K⁻¹ and the equilibrium concentrations of N₂ and O₂ is:

[tex][N_2O]=\frac{K^{-1}}{K_1}\times [N_2][O_2][/tex]

Explanation :

As we are given that:

The rate of reaction in forward direction = [tex]R_f=K_1\times [N_2O][/tex]

The rate of reaction in backward direction = [tex]R_b=K^{-1}\times [N_2][O_2][/tex]

As we know that at equilibrium, rate of forward reaction is equal to the rate of backward reaction.

So,

[tex]R_f=R_b[/tex]

[tex]K_1\times [N_2O]=K^{-1}\times [N_2][O_2][/tex]

The expression that gives the equilibrium concentration of N₂O in terms of K₁, K⁻¹ and the equilibrium concentrations of N₂ and O₂ is:

[tex][N_2O]=\frac{K^{-1}}{K_1}\times [N_2][O_2][/tex]

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