Answer:
1635 people
Step-by-step explanation:
The proportion of people with two or more jobs in the sample  is Â
7/50 = 0.14
The z-value that gives us a 98% confidence level is 2.33 (this means that 98% of the area under the normal curve N(0;1) is between -2.33 and 2.33)
If we use Simple Random sampling, the size of the sample should be
[tex]n=\displaystyle\frac{z^2p(1-p)}{e^2}[/tex]
where z is the z-value which gives us the desired confidence level, p the proportion and e the error. In our case
z = 2.33
p = 0.14
e = 2% = 0.02
So, the sample size should be
[tex]n=\displaystyle\frac{(2.33)^2*0.14*0.86}{(0.02)^2}=1634.0989\approx 1635[/tex]
rounding up to the nearest integer.
