Answer:
23.9Km
Explanation:
The following data are given
diameter, d =14cm =0.14m
r=d/2=0.07m
length,l=60cm
current,i=2.2A
magnetic field of 2.5kG we convert to telsa
[tex]1 Gauss=10^{-4}T\\hence \\2500G=2500*10^{-4}\\0.25T[/tex]
First we determine the total number of turns from
[tex]B=\frac{U_{0}NI}{h}\\U_{0}=4\pi *10^{-7}\\N=\frac{Bh}{U_{0}*I} \\N=\frac{0.25*0.6}{4\pi *10^{-7}*2.2}\\ N=54257 turns\\[/tex]
Sine it is circular, the length of the wire is
[tex]L=N*2\pi r\\L=54257*2\pi *0.07\\L=23864\\L=23.9Km[/tex]
