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A crate is pulled to the right with a force of 73.3 N, to the left with a force of 115.8 N, upward with a force of 606.7 N, and downward with a force of 247.6 N. What is the net external force in the x direction? Answer in units of N.

Respuesta :

lublana

Answer:

-42.5 N

Explanation:

We are given that

[tex]F_1=73.3 N[/tex](right)

[tex]F_2=115.8 N[/tex](left)

[tex]F_3=606.7 N[/tex](upward)

[tex]F_4=247.6 N[/tex](downward)

We have to find the net external force in the x- direction.

Net external force along x- direction=[tex]F_x=F_1-F_2[/tex]

[tex]F_x=F_1-F_2=73.3-115.8=-42.5 N[/tex]

Net external force along y- direction=[tex]F_y=F_3-F_4[/tex]

[tex]F_y=F_3-F_4=606.7-247.6=359.1 N[/tex]

Hence, the net external force in the x- direction=-42.5 N

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