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Input numbers and segregate them by placing their values into even or odd vectors based upon their value being even or odd. Then fill a 2-D array with the first column containing the contents of the even vector and the second column containing the odd vector. Output the result and display the contents of the vectors and array.

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teobguan2019

Answer:

The solution code is written in Python

  1. input_numbers = [5, 7, 1, 12, 9, 34, 22, 97, 112]
  3. evenVec = []
  4. oddVec = []
  6. for x in input_numbers:
  7.    if x % 2 == 0:
  8.        evenVec.append(x)
  9.    else:
  10.        oddVec.append(x)
  12. num2D = [evenVec, oddVec]
  14. print(num2D)

Explanation:

Let's create a sample input numbers that mixed with odd and even values (Line 1)

Next, create evenVec and oddVec variables to hold the even and odd numbers from the input_numbers (Line 3 - 4).

Create a for-loop to traverse through the input_numbers and check if current number, x, is divisible by 2 using the modulus operator %. If so, x % 2 will be evaluated to 0 and append the current x to evenVec or else append to oddVec (Line 6 - 10).

Next, create a variable num2D to hold the two dimensional arrays with first column is evenVec and second column is oddVec (Line 12).

When printing the num2D (Line 14), we shall get

[[12, 34, 22, 112], [5, 7, 1, 9, 97]]

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