Respuesta :
Answer:
(a) 1
(b) -1
(c) 1
Explanation:
In this type of questions use the strategy to look for placing the products and reactants on their right side.
For b) we notice MgO is a product in our reaction, therefore reverse the equation, the coefficient is 1 since there is one mol MgO product
Mg2+(aq) + 2Cl–(aq) + H2O(l) →  MgO(s) + 2HCl(aq)
We can notice that HCl is not a product in our final reaction, so we want to cancel it. If we add (a) to the one above, we get:
Mg(s) + 2HCl(aq) → Mg2+(aq) + 2Cl–(aq) + H2(g)
                  +
Mg2+(aq) + 2Cl–(aq) + H2O(l) →  MgO(s) + 2HCl(aq)
                                              Â
Mg(s)     +      H2O(l)      →    H2(g) + MgO(s)
Finally adding this last equation to (c) we get our sought equation:
Mg(s)     +      H2O(l)      →    H2(g) + MgO(s)
                     +
H2(g) Â Â Â Â Â Â + Â Â 0.5O2(g) Â Â Â Â H2O(l)
                                               Â
Mg(s)      +     0.5O2(g) →     MgO(s)
So we only needed to reverse the sign for the first equation, and our answer should be
(a) 1
(b) -1
(c) 1