Answer:
The value of ΔH when 21.9 grams of hydrogen gas reacts with an excess of oxygen gas is 2,647.71 kilo Joules.
Explanation:
[tex]H_2+\frac{1}{2}O_2\rightarrow H_2O,\Delta H=-241.8 kJ[/tex]
Mass of hydrogen gas = 21.9 g
Moles of hydrogen gas = [tex]\frac{21.9 g}{2 g/mol}=10.95 mol[/tex]
When 1 mole of hydrogen gas reacts with an excess oxygen gas it gives 241.8 kJ of heat.
Then 10.95 moles hydrogen gas will give :
[tex]241.8 kJ\times 10.95 =2,647.71 kJ[/tex]
The value of ΔH when 21.9 grams of hydrogen gas reacts with an excess of oxygen gas is 2,647.71 kilo Joules.
