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A student adds 10.00 mL of a 2.0 M nitric acid solution to a 100.00 mL volumetric flask. Next, 50.00 mL of a 0.00500 M solution of KSCN is added by pipet. Deionized water is added to the flask to dilute the solution to the 100.00 mL mark. What is the concentration of the new solution?

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Answer:

0,20M of nitric acid

0,00250M of KSCN

Explanation:

For nitric acid, the dilution is from 10,00mL to 100,00mL. That is a 1/10 dilution. As the initial concentration of nitric acid is 2,0M, the new concentration is: 2,0M× (1/10) = 0,20M of nitric acid

For KSCN the dilution is from 50,00mL to 100,00mL, that is a dilution 1/2. Thus, the new concentration of KSCN is:

0,00500M × (1/2) = 0,00250M of KSCN

I hope it helps!

The concentration of the new solution is 0,20M of nitric acid and 0,00250M

Calculation of the concentration:

Since For nitric acid, the dilution is from 10,00mL to 100,00mL. It should be 1/10 dilution. Since the initial concentration of nitric acid is 2,0M, the new concentration is

= 2,0M× (1/10)

= 0,20M of nitric acid

Now the dilution is from 50,00mL to 100,00mL, that is a dilution 1/2. So, the new concentration is:

= 0,00500M × (1/2)

= 0,00250M

Learn more about concentration here; https://brainly.com/question/23935447

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