Answer:
The work done by the motor of the compressor is 1.20 x 10^5 J.
Explanation:
As the change in the internal energy is given as 1.20 x 10^5 J, and as there is no amount of heat added in the system this is given as
[tex]\Delta U=Q+W\\1.20\times 10^5=0+W\\1.20\times 10^5=W\\[/tex]
So the work done by the motor of the compressor is 1.20 x 10^5 J.
Answer:
Work done W = 1.20×10⁵ J
Explanation:
Air conditioners operate on the same principle as refrigerators.
Consider an air conditioner that has 7.00kg of refrigerant flowing
through its circuit each cycle. The refrigerant enters the evaporator
coils in phase equilibrium, with 54.0% of its mass as liquid and the
rest as vapor. It flows through the evaporator at a constant pressure
and when it reaches the compressor 95% of its mass is vapor.
In each cycle, the change in internal energy of the refrigerant when
it leaves the compressor is 1.20×10⁵ J . What is the work done by the
motor of the compressor?
The compressor usually takes in low-pressure and low-temperature vapor and then compresses it adiabatically to high-pressure and high-temperature vapor.
Since the compressor performs an adiabatic compression, that means there is no exchange of heat while the refrigerant is in the compressor. Using the first law of thermodynamics to determine work done W.
ΔU = Q - W where ΔU is change in internal energy, Q is heat added which is zero as there is no exchange of heat and W is work done.
Therefore ΔU = W= 1.20×10⁵ J
