Respuesta :
Answer:
the rate of change is f'(t) = (-8.08)*( 0.98^t )
Step-by-step explanation:
If the function is
f(t)= 400* (0.98)^t
then the rate of change of f(t) , that is f'(t)=df(t)/dt is
f'(t) = 400* d ( 0.98^t ) / dt
since the derivative of a function of the type g(x) = a^x is g'(x)= ln(a) * a^x , then
f'(t) = 400* d ( 0.98^t ) / dt = 400*ln (0.98) * ( 0.98^t )
f'(t) = (-8.08)*( 0.98^t )
