Answer:
The optimum maintenance crew size is 2 workers.
Explanation:
M/M/1 model for all: -
With one worker: λ= 3 per hour.
µ= 5 per hour.
Average number in system = λ/µ-λ =[tex]\frac{3}{5-3}[/tex] = 1.5.
- With two workers: λ= 3 per hour µ= 7 per hour.
Average number in system = λ/µ-λ−=[tex]\frac{3}{7-3}[/tex]=0.75.
- With three workers: λ= 3 per hour, µ= 8 per hour.
Average number in system = λ/µ-λ−=[tex]\frac{3}{8-3}[/tex]=0.6.
# workers λ µ (ns) ($25*(ns)) ($4*(no.of workers) Total cost
1 3 5 1.5 37.50 4 $41.50
2 3 7 0.75 18.75 8 $26.75
3 3 8 0.6 15 12 $27.00
The optimum maintenance crew size is 2 workers.