In this example the motion is in a vertical circle. Passengers in a carnival ride travel in a circle with radius 5.0 m. The ride moves at a constant speed and makes one complete circle in a time T=4.0s. What is the acceleration of the passengers?

If the ride increases in speed so that T=3.0s, what is arad? (This question can be answered by using proportional reasoning, without much arithmetic.)

Respuesta :

Answer:

a. [tex]12.3m/s^{2}[/tex]

b. [tex]21.93m/s^{2}[/tex]

Explanation:

From the data given, the radius is 5.0m, and the time taken to complete one circle is 4.0secs

Since the motion is in a circular part, we can conclude that the total distance covered in this time is given as circumference of the circle.

which is expressed as

[tex]Distance=2\pi R[/tex]

To determine the speed, we use the equation

[tex]speed=\frac{distnce}{time}\\ Speed=\frac{2\pi R}{time}\\ speed=\frac{2\pi*5 }{4}\\ Speed=7.85m/s[/tex]

The acceleration as required is expressed as

[tex]a=\frac{v^{2}}{r}\\ a=\frac{7.85^{2}}{5}\\ a=12.3m/s^{2}[/tex]

if the speed increase and it takes 3secs to complete one circle, the speed is

[tex]speed=\frac{distnce}{time}\\ Speed=\frac{2\pi R}{time}\\ speed=\frac{2\pi*5 }{3}\\ Speed=10.47m/s[/tex]

and the acceleration becomes

[tex]a=\frac{v^{2}}{r}\\ a=\frac{10.47^{2}}{5}\\ a=21.93m/s^{2}[/tex]