Answer:
0.39 g/L is the concentration of albumin
Explanation:
We assume volumes additive
0.20 mL (volume of solute) + 2.84 ml (volume of solvent) = 3.04 mL (volume of solution)
Let's determine thee mass of solute. We first convert, the mL to L.
0.20 mL. 1 L/1000mL = 0.0002 L
We use the concentration to determine the mass → 0.0002 L . 6 g/L =
0.0012 g of albumin.
This is are the mass of solute in our solution, which has a volume of 3.04 mL. Let's convert the mL to L → 3.04mL. 1 L/1000mL = 0.00304 L
Concentration (g/L) = 0.0012 g / 0.00304 L = 0.39 g/L
0.39 g/L is the concentration of albumin.
Volume of solution:
0.20 mL (volume of solute) + 2.84 ml (volume of solvent) = 3.04 mL (volume of solution)
0.20 mL. 1 L/1000mL = 0.0002 L
We use the concentration to determine
Mass = [tex]0.0002 L . 6 g/L = 0.0012 g[/tex] of albumin.
Calculation for concentration:
Concentration (g/L) = [tex]0.0012 g / 0.00304 L = 0.39 g/L[/tex]
Thus, the concentration of albumin is 0.39 g/L.
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