Answer : The rate for a reaction will be [tex]0.14Ms^{-1}[/tex]
Explanation :
The balanced equations will be:
[tex]A(g)+B(g)\rightarrow AB(g)[/tex]
In this reaction, [tex]A[/tex] and [tex]B[/tex] are the reactants.
The rate law expression for the reaction is:
[tex]\text{Rate}=k[A]^2[B]^1[/tex]
or,
[tex]\text{Rate}=k[A]^2[B][/tex]
Now, calculating the value of 'k' by using any expression.
[tex]\text{Rate}=k[A]^2[B][/tex]
[tex]0.385=k(2.00)^2(2.00)[/tex]
[tex]k=0.0481M^{-2}s^{-1}[/tex]
Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.
[tex]\text{Rate}=k[A]^2[B]^0[C]^1[/tex]
[tex]\text{Rate}=(0.0481)\times (1.48)^2(1.32)^1[/tex]
[tex]\text{Rate}=0.14Ms^{-1}[/tex]
Therefore, the rate for a reaction will be [tex]0.14Ms^{-1}[/tex]
