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An electronic device was manufactured in two versions. There were 1,500x first version devices sold at a price of $9x per device. The second version devices were sold at a price that was $20 more than the first version, but there were 400 more first version devices sold. Which of the following will give the amount earned from the sales of the second version of the device?
A. N(x) = 13,500x2 + 599,820x - 8,000
B. N(x) = 13,500x2 + 600,180x + 8,000
C. N(x) = 13,500x2 + 26,400x - 8,000
D. N(x) = 13,500x2 + 33,600x + 8,000

Respuesta :

Answer:

A. N(x) = 13,500x2 + 599,820x - 8,000

Step-by-step explanation:

We can find out the number of sales by multiplying the number of the device sold with the price of the device. The second device sold 400 less than the first version, and there is a total of 1500x number of first version devices sold. Then the number of second devices sold will be:  

Device sold = 1500x-400

The price of the second device is $20 higher than the first device, while the price of the first version device is $9x. The price for the second version device will be:

Device price= 20+9x

The sales will be:

sales= device sold * device price

sales=  (1500x-400)* (20+9x)

sales= 30000x+13500[tex]x^{2}[/tex] -8000 +3600x

sales = 13500[tex]x^{2}[/tex] + 33600x - 8000

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