Respuesta :
Answer:
Explanation:
The formula for determining the volume of a spherical steel ball is expressed as
Volume = (4/3)πr³
Where
r represents the radius of the spherical steel ball.
π is a constant whose value is 3.14
Diameter = 9.4 mm
Radius = diameter/2 = 9.4mm/2 = 4.7mm
Volume = 4/3 × 3.14 × 4.7³
Volume = 434.67 mm³
Density = mass/volume
Mass = 3.475g
Density = 3.475/434.67
Density = 0.008 g/mm³
The density of the spherical steel ball is 7988.5 kg/m³
Density, mass and volume
From the question, we are to determine the density of the steel.
Density is given by the formula
[tex]Density = \frac{Mass}{Volume}[/tex]
First, we will determine the volume of the spherical steel ball
The volume is given by the formula,
[tex]V = \frac{4}{3}\pi r^{3}[/tex]
Where r is the radius
From the given information,
Diameter, d = 9.40 mm
Then, [tex]r =\frac{9.40}{2}[/tex]
r = 4.70 mm = 0.0047 m
Therefore,
[tex]V = \frac{4}{3} \times 3.142 \times (0.0047)^3[/tex]
V = 4.35 × 10⁻⁷ m³
Now, for the density of the steel
From the given information,
Mass of the steel ball = 3.475 g = 0.003475 kg
Therefore,
[tex]Density = \frac{x0.003475}{4.35 \times 10^-7}[/tex]
Density = 7,988.5 kg/m³
Hence, the density of the spherical steel ball is 7988.5 kg/m³
Learn more on Density, Mass and Volume here: https://brainly.com/question/11409334?section=related_q
