33. A bicyclist rides 30 mi against a wind and returns 30 mi with the wind. His average speed for the return trip is 5 mph faster. How fast did the cyclist ride against the wind if the total time of the trip was 5 hr?

Respuesta :

Answer:

30 miles÷ 2.5

2.5 hours÷ 2.5

=  

12 miles

1 hour

=  

12 miles

hour

= 12 miles per hour

Hope this helps~

All the love, ya boi Fraser :)

The speed is the distance covered by an object at a particular time. The speed of the against the wind is 10 miles per hour.

What is speed?

The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.

[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]

Given that a bicyclist rides 30 mi against a wind and returns 30 mi with the wind. His average speed for the return trip is 5 mph faster. Therefore, we can write the following details,

Distance in the direction of wind, d = 30 miles

Distance in the direction against the wind, d = 30 miles

Speed when riding in the direction of the wind, s = x + 5

Speed when riding against the direction of the wind, S = x

Also, the total time = 5 hrs

Now, the equation of the total time can be written as,

(30 / x+5) + (30 / x) = 5

30x + 30x + 150 = 5x(x+5)

60x + 150 = 5x² + 25x

5x² - 35x - 150 = 0

5x² - 50x + 15x - 150 = 0

5x(x - 10) + 15(x - 10) = 0

(5x + 15)(x - 10) = 0

x = -3, 10

Hence, the speed of the against the wind is 10 miles per hour.

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