4x - y + 3 =0 is the equation of the line
Step-by-step explanation:
Given:
The slope of the line = 5
The points through with the line passes = (0,3)
To Find:
The equation of the line =?
Solution:
The equation y = mx + b
where m is the slope and (0,b) is the y-intercept.
The slope is given which is m = 4 and a point (0,3)
Then you can use slope-point equation
[tex]y - y_o = m(x - x_o)[/tex]
where [tex](x_o,y_o)[/tex] is the given point
y - (3) = 4(x - 0)
y - 3 = 4(x)
y = 4x - 22
y - 3 = 4x
4x - y + 3 = 0
The equation of the line with a slope of 4 and passing through (0,3) is
4 x - y + 3 = 0
Explanation:
Slope, m = 4
Points = ( 0,3 ) - ([tex]x_{1}[/tex], [tex]y_{1}[/tex])
Equation of the line = ?
We know,
The formula used to find the equation of a line when points and slope are given is
(y - [tex]y_{1}[/tex]) = m ( x - [tex]x_{1}[/tex])
Where, [tex]x_{1}[/tex] and [tex]y_{1}[/tex]are the points
m is the slope
Therefore,
y - 3 = 4 ( x - 0)
y - 3 = 4 x
4 x - y + 3 = 0
Therefore, The equation of the line with a slope of 4 and passing through (0,3) is 4 x - y + 3 = 0
