Answer:
The x component of the electric field at y=2m is [tex]E_{x}=17.97\frac{N}{C}[/tex]
Explanation:
For a linear charge, using Gauss Law, we get that the Electric field (radial) has the following form
[tex]E=\frac{\lambda}{2\pi\epsilon_{0}r}[/tex]
where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data. So
[tex]E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}[/tex]
is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.
The electric field is a physical field occupied by a charged particle on another particle in its surroundings. The x component of the electric field at y = 2 m on the y axis will be Eₓ = 17.97 N/C.
It is a physical field occupied by a charged particle on another particle in its surrounding. It is denoted by the E. Its unit is N/C.
The given data in the problem is;
λ is the uniform linear charge= 2.0 nC/m
The limits value for x axis from x = 0 to x = 3 m.
Eₓ is the x component of the electric field=?
The gauss law for the linear charge is given as;
[tex]\rm E= \frac{\lambda}{2 \pi \epsilon_0 r} \\\\ \rm E= \frac{2 \times 10^{-9}\times(3-0) }{2 \times 3.14 \times 9 \times 10^9 \times 2}[/tex]
[tex]\rm E_x = 17.97\N/C.[/tex]
Hence the x component of the electric field at y = 2 m on the y axis will be Eₓ = 17.97 N/C
To learn more about the electric field refer to the link;
https://brainly.com/question/26690770
