This is an incomplete question, the complete question image is attached below.
Answer : The chemical formula for the limiting reactant is, [tex]NO[/tex]
Explanation :
In the given image reaction we conclude that, there are 5 molecules of [tex]H_2[/tex] and 4 molecules of [tex]NO[/tex] present on reactant side of the reaction and there are 2 molecules of [tex]N_2[/tex], 1 molecule of [tex]H_2[/tex] and 4 molecules of [tex]H_2O[/tex] present on product side of the reaction.
Thus, the chemical reaction will be:
[tex]5H_2+4NO\rightarrow 2N_2+H_2+4H_2O[/tex]
From this we conclude that, 5 molecules of [tex]H_2[/tex] react with 4 molecules of [tex]NO[/tex] that means, [tex]NO[/tex] is a limiting reactant and [tex]H_2[/tex] is an excess reactant.
Thus, the chemical formula for the limiting reactant is, [tex]NO[/tex]
