Given value is:
Absorbance,
As we know that,
→ [tex]A = -log \ T[/tex]
or,
→ [tex]T = 10^{-A}[/tex]
By substituting the value, we get
[tex]= 10^{-0.255}[/tex]
[tex]= 55.6[/tex] (%)
Thus the above answer is appropriate.
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