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PLLLLZ HELP Find the magnitude of the horizontal and vertical components of a force of 465 newtons at a bearing of 19° from the horizontal. Round to the nearest whole number.

horizontal component: 440 N, vertical component: 151 N

horizontal component: 440 N, vertical component: 25 N

horizontal component: 151 N, vertical component: 314 N

horizontal component: 151 N, vertical component: 440 N

Respuesta :

joseaaronlara

Answer:

The answer to your question is the first choice

Step-by-step explanation:

Data

Force = 465 N

bearing = 19°

Process

1.- Find the components using trigonometric functions

To find the horizontal component use cosine

To find the vertical component use sine

            cos Ф = x/F                     sin Ф = y/F

Substitution

            cos 19 = x/465                sin 19 = y/465

            x = 465 cos 19                  y = 465 sin 19

            x = 439 N                          y = 151.39 N

2.- Rounding to the nearest number

Horizontal component = 440N

Vertical component = 151 N            

yuly3000

Answer:

horizontal component: 440 N, vertical component: 151 N

Step-by-step explanation:

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