Respuesta :
Answer:
The angular acceleration required is 0.1765 rad/ [tex]s^2[/tex]
Explanation:
The radius of the bicycle wheel has a radius of 0.42 m.
The acceleration is for time, t = 6.8 seconds.
Initial angular velocity is given as [tex]\omega_{0}[/tex] = 5.5 rad/s
Final angular velocity is given as [tex]\omega_{f}[/tex] = 6.7 rad/s
Therefore from the formula for angular speed we get
[tex]\omega_{f}[/tex] = [tex]\omega_{0}[/tex] + ([tex]\frac{d\omega}{dt}[/tex] [tex]\times[/tex] t), where t is the time in seconds.
Therefore we get
6.7 = 5.5 + (6.8 × [tex]\frac{d\omega}{dt}[/tex] )
Therefore we get the angular acceleration, [tex]\frac{d\omega}{dt}[/tex] = [tex]\frac{(6.7 - 5.5 }{6.8} = 0.1765 rad/ s^2[/tex]
The angular acceleration required is 0.1765 rad/ [tex]s^2[/tex]
