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After emptying her lungs, a person inhales 4.2 L of air at 0.0oC and holds her breath. How much does the volume of the air increase as it warms to her body temperature of 37oC?

Respuesta :

MechEngineer

Answer:

0.57 liters

Explanation:

0 C = 273 K

37 C = 37 + 273 = 310 K

Assume ideal gas under constant atmospheric pressure. We know that volume and temperature are proportional to each other

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

[tex]V_2 = \frac{V_1 T_2}{T_1} = \frac{4.2 * 310}{273} = 4.77 L[/tex]

Sp the air volume must have increased by 4.77 - 4.2 = 0.57 Liters

onyebuchinnaji

The increase in the volume of air in her lungs is 0.58 L.

The given parameters;

  • initial volume of air, = 4.2 L
  • initial temperature, = 0 ⁰C = 273 K
  • final temperature, = 37 ⁰ = 310 K

The final volume of air in her lungs is calculated by applying Charles law;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{4.2 \times 310}{273} \\\\V_2 = 4.78 \ L[/tex]

The increase in the volume of air in her lungs is calculated as follows;

[tex]\Delta V = 4.78 - 4.2\\\\\Delta V = 0.58 \ L[/tex]

Thus, the increase in the volume of air in her lungs is 0.58 L.

Learn more here:https://brainly.com/question/16927784

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