Answer:
192851877 s or 6.1 years
Explanation:
1.8 km = 1800 m
2.93 kW = 2930 W
First we calculate the potential energy needed to pump [tex]3.2\times10^7kg[/tex] of water to 1800 m high. Suppose g = 9.81 m/s2:
[tex]E = mgh = 3.2*10^7*1800*9.81 = 5.65 \times 10^{11} J[/tex]
Then we can calculate the time it takes for a pump with power of 2930 W to perform that amount of energy
[tex]t = E/P = 5.65 \times 10^{11}/2930 = 192851877 s = 192851877.1/(60*60) = 53570 hours = 53570 / 24 = 2232 days = 2232 / 365.25 = 6.1 years[/tex]
Answer:
Explanation:
The potential energy contained in the mass of water by using the equation for gravitational potential energy, G.P.E = mass x height x acc. due to gravity.
E = 3.2 x 10^7 × 1.80 x 1000 × 9.81
= 5.65 × 10^11 J
Power = Work done/time taken
2.93 × 10^3 = 5.65 × 10^11/t
T = 5.488 10^11/2700
= 1.93 × 10^8 s.
Time taken, t = 1.93 × 10^8 s
= 6.12 years.
