The following is the arrangement of the given molecules in decreasing order of mass: [tex]\text{ Fe2O3} > \text{C6H14} > \text{CaCO} > \text{NO2}[/tex]
Solution:
First inorder to arrange the elements in descending order of their mass we have to calculate the molecular mass of each element. The calculation is as follows:
Mass of C6H14:
[tex]C\rightarrow6\times12.01 = 72.06[/tex]
[tex]H\rightarrow14\times1.008 = 14.112[/tex]
Mass of C6H14 is 86.172
Mass of NO2:
[tex]N\rightarrow1\times14.0067 = 14.0067[/tex]
[tex]O\rightarrow2\times15.9994 = 31.9988[/tex]
Mass of NO2 is 46.0055
Mass of Fe2O3:
[tex]Fe\rightarrow2\times55.845 = 111.69[/tex]
[tex]O\rightarrow3\times15.9994 = 47.9982[/tex]
Mass of Fe2O3 is 159.6882
Mass of CaCO:
[tex]Ca\rightarrow1\times40.078 = 40.078[/tex]
[tex]C\rightarrow1\times12.01 = 12.01[/tex]
[tex]O\rightarrow1\times15.9994 = 15.9994[/tex]
Mass of CaCO will be 68.0874
So, the order will be [tex]159.6882>86.172>68.0874>46.0055[/tex] which is [tex]\text{ Fe2O3} > \text{C6H14} > \text{CaCO} > \text{NO2}[/tex]
