Respuesta :
The perimeter of the large hexagon is equal to 12 units.
Explanation:
Given,
The perimeter of small hexagon = [tex]2\sqrt{3}[/tex]
To find, the perimeter of the large hexagon = ?
We know that,
The perimeter of the large hexagon
[tex]= \dfrac{6}{\sqrt{3}}[/tex] × The perimeter of small hexagon
= [tex]\dfrac{6}{\sqrt{3}} \times 2\sqrt{3}[/tex]
= 6 × 2
= 12 units
∴ The perimeter of the large hexagon = 12 units
Thus, the perimeter of the large hexagon is equal to 12 units.
Answer:
4
Explanation:
we can set up a 120,30,30 isosceles triangle than divide it into two 30 60 90 triangles then 2 rt 3 divide it by 12 (the hexagon and the two triangle) then we get 1/6 rt 3 after that we get 1/3 as the side length but since we divide by 2 we need to multiply by two thus getting us 2/3 but to get the perimeter, we need to multiply by 6 and our final answer is 4
