The amount of time it takes for an investment to double in value is called the doubling time for the investment. If the doubling time for a $10,000 investment is seven years and the interest on the investment is compounded annually, what must be the annual rate of interest?

Respuesta :

Answer:

Compounding interest rate, r = 10.41%

Explanation:

As the investment will be doubled after 7 years from now, the future value of the current investment will be = $10,000 Ă— 2 = $20,000

Therefore,

Number of periods (years), n = 7

Future value, FV = $20,000

Principal = Present Value, PV = $10,000

we have to determine the compounding interest rate, r.

We know,

r = [tex][(\frac{FV}{PV})^{\frac{1}{n}} - 1][/tex]

Putting the values into the formula, we can get,

r = [tex][(\frac{20,000}{10,000})^{\frac{1}{7}} - 1][/tex]

or, r =[tex](2^{\frac{1}{7}} - 1)[/tex]

With the help of calculator, we can find the value of [tex]2^{\frac{1}{7}}[/tex] = 1.1041

or, r = (1.1041 - 1)

or, r = 0.1041

Therefore, interest rate = 10.41%