Answer:
y = - [tex]\frac{16}{9}[/tex] x + [tex]\frac{40}{9}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is y = mx + c
Given
16x + 9y = 40 ( subtract 16x from both sides )
9y = - 16x + 40 ( divide all terms by 9 )
y = - [tex]\frac{16}{9}[/tex] x + [tex]\frac{40}{9}[/tex] ← in slope- intercept form
Answer:
y= -16/9x+ 40/9
Step-by-step explanation:
Subtract 16x to both sides to isolate the y variable.
16x+9y= 40
-16x -16x
This gives us...
9y= -16x+40
Now, divide by 9 to isolate the y variable.
9y= -16x+40
9 9 9
y= -16/9x+ 40/9
or, [tex]y = \frac{40 - 16x}{9}[/tex] [tex]= \frac{40}{9}[/tex] [tex]- \frac{16x}{9}[/tex]
or, [tex]y = (- \frac{16}{9})x + \frac{40}{9}[/tex]
