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What is the magnitude of the electric field strength between them, if the potential 7.95 cm from the zero volt plate (and 2.05 cm from the other) is 413 V?

Respuesta :

Answer:

ΔVab = Ed

ΔVab = Va-Vb = Va-V0 = Va

E = Va/ d

   = 413V / 0.0795 m

    = 5194.97 V/M

Explanation:

the potential difference between two uniform plates is calculated by the formula of electric field.

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