Respuesta :
Answer:
226.0 grams of H2O is produced
Explanation:
Step 1: Data given
Mass of methanol = 201 grams
Molar mass methanol = 32.04 g/mol
Step 2: The balanced equation
2CH3OH + 3O2 → 2CO2 + 4H2O
Step 3: Calculate moles methanol
Moles methanol = mass methanol / molar mass
Moles methanol = 201.0 grams / 32.04 g/mol
Moles methanol = 6.27 moles
Step 4: Calculate moles H2O
For 2 moles methanol we need 3 moles O2 to produce 2 moles CO2 and 4 moles H2O
For 6.27 moles methanol we'll have 2*6.27 = 12.54 moles H2O
Step 5: Calculate mass H2O
Mass H2O = moles H2O * molar mass H2O
Mass H2O = 12.54 moles * 18.02 g/mol
Mass H2O = 226.0 grams
226.0 grams of H2O is produced
The mass of water produced by 201 grams of methanol has been 451.685 grams.
According to the balanced chemical equation, the complete combustion of 2 moles of methanol produces 4 moles of water.
Moles can be calculated by the expression:
Moles = [tex]\rm \dfrac{Mass}{Molecular\;mass}[/tex]
The moles of methanol in 201 g has been:
Moles of methanol = [tex]\rm \dfrac{201\;g}{32.04\;g/ml}[/tex]
Moles of methanol = 6.273 mol.
From the equation:
1 mole methanol = 4 moles water
6.273 moles methanol = 6.273 × 4 moles water
6.273 moles methanol = 25.093 moles water.
The moles of water produced by 201 grams of methanol have been 25.093 mol.
The mass of water can be calculated as:
Mass = moles × molecular mass
Mass of water produced = 25.093 mol × 18 g/mol
Mass of water produced = 451.685 grams.
The mass of water produced by 201 grams of methanol has been 451.685 grams.
For more information about the mass-produced in a chemical reaction, refer to the link:
https://brainly.com/question/4769843
