Respuesta :
Explanation:
According to the Newton's second law of motion,
F = ma
= [tex]\frac{m(v - u)}{t}[/tex]
or, v = [tex]\frac{Ft}{m} + u[/tex]
= [tex]\frac{2.58 \times 2.62 sec}{0.561 kg} + 0[/tex]
= 12.049 m/s (+x direction)
Therefore, we can conclude that the velocity at the end of this interval is 12.049 m/s.
Answer:
Velocity at the end of this interval is [tex]12.049[/tex] meter per second
Explanation:
As we know that
[tex]F = m * a[/tex]
Where F signifies the force, m signifies the mass and a signifies the acceleration
Acceleration is the rate of change of speed or velocity and it can be represented as
[tex]a = \frac{v-u}{t}[/tex]
where v is the final velocity, u is the initial velocity and t is the time taken to change the velocity.
Here, the object is at rest , thus its initial velocity is zero.
Substituting the given values in above equation, we get -
[tex]2.58 = 0.561 * \frac{v - 0}{2.62} \\v = \frac{2.58 * 2.62}{0.561} \\v = 12.049 \frac{m}{s}[/tex]
