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ANSWER ASAP--Suppose an astronaut can jump vertically with an initial velocity of 5 m/s. The time that it takes him to touch the ground is given by the equation 0 = 5t - 0.5at2. The time t is in seconds and the acceleration due to gravity a is in m/s2. How long will it take him to reach the ground if he jumps on Earth where a = 9.8 m/s2?

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Poltergeist

Answer:

It will take the astronaut 1.02 seconds to reach the ground.

Step-by-step explanation:

If [tex]a = 9.8m/s^2[/tex], then our equation becomes

[tex]5t-0.5(9.8)t^2=0[/tex]

[tex]5t-4.9t^2=0[/tex]

Add [tex]4.9t^2[/tex] to both sides and get

[tex]5t = 4.9t^2[/tex],

and dividing both sides by [tex]t[/tex], we get:

[tex]5 = 4.9t[/tex]

[tex]$t = \frac{5}{4.9} $[/tex]

[tex]\boxed{t = 1.02s}[/tex]

Therefore, it takes the astronaut 1.02 seconds to reach the ground.

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