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An electric field has a strength of 100 N/C or 100 V/m between two large charged plates. The potential difference across the plates is 40 V. What is the distance between the two plates

Respuesta :

Answer:

The distance between the two plates is 0.4 m.

Explanation:

Given that,

Electric field strength = 100 N/C

Potential difference = 40 V

We need to calculate the distance between the two plates

Using formula of electric field

[tex]E=\dfrac{V}{d}[/tex]

[tex]d=\dfrac{V}{E}[/tex]

Where, E = electric field strength

V = potential difference

d = distance between the two plates

Put the value into the formula

[tex]d=\dfrac{40}{100}[/tex]

[tex]d=0.4\ m[/tex]

Hence, The distance between the two plates is 0.4 m.

asuwafohjames

The distance between the plates is 0.4 m.

The distance between the two plates can be calculated using the formula below.

Formula:

  • E = V/d.......................... Equation 1

Where:

  • E = Electic field strength
  • V = Potential difference
  • d = distance between the two plates.

Make d the subject of the equation.

  • d = V/E...................... Equation 2

From the question,

Given:

  • V = 40 V
  • E = 100 V/m

Substitute these values into equation 2

  • d = 40/100
  • d = 0.4 m

Hence, The distance between the plates is 0.4 m.

Learn more about electric fields Strengths here: https://brainly.com/question/1216683

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