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Since both HBr and KOH are strong, we expect these reactions to occur fully. You mix 2 moles of HBr with 3 moles of KOH in enough water to make 1 L of solution. What is the pH of your final solution?

Respuesta :

Answer: pH = 14

Explanation: Please see the attachments below

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Ver imagen Abdulazeez10
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The pH of the resulting solution is 14.

We have the following information;

Number of moles of HBr =  2  moles

Number of moles of KOH = 3 moles

Volume of solution = 1 L

Now;

The equation of the reaction is;

HBr + KOH ------> KBr + H2O

The limiting reactant in this case is HBr, the number of moles of excess KOH is obtained from 3 moles - 2 moles = 1 mole

Concentration of excess KOH = 1mole/ 1 L = 1 M

Now the pOH of the solution = -log [1M] = 0

Since pH + pOH = 14

pH = 14

The pH of the resulting solution is 14.

Learn more about pH: https://brainly.com/question/8592296

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