contestada

A single-celled animal called a paramecium propels itself quite rapidly through water using its hair-like cilia. A certain paramecium experiences a drag force of F d r a g = − b v 2 in water, where the drag coefficient b is approximately 0.290 kg/m . If the paramecium's speed v is 0.000157 m/s , what is the magnitude of the propulsion force that the creature must generate to move at this constant speed?

Respuesta :

Answer:

The magnitude of the propulsion force  is [tex]7.14\times10^{-9}\ N[/tex]

Explanation:

Given that,

Drag coefficient b= 0.290 kg/m

Speed v = 0.000157 m/s

The drag force is

[tex]f_{d}=-bv^2[/tex]

Since it is given that animal have to generate constant terminal speed.

So if speed becomes constant then we can say its acceleration a = 0

So, The net force is zero.

We need to calculate the magnitude of the propulsion force

Using balance equation

[tex]F_{applied}+F_{drag}=F_{net}[/tex]

[tex]F_{applied}=-F_{drag}[/tex]

[tex]F_{applied}=-(bv^2)[/tex]

Put the value into the formula

[tex]F_{applied}=-(-0.290\times(0.000157)^2)[/tex]

[tex]F_{applied}=7.14\times10^{-9}\ N[/tex]

Hence, The magnitude of the propulsion force  is [tex]7.14\times10^{-9}\ N[/tex]

Otras preguntas