Answer:
Option c. 6 moles of Al
Explanation:
The chemical reaction is:
4Al (s) + 3O₂ (g) → 2Al₂O₃(s)
I have 4.50 moles of oxygen. Ratio is 2:3
If 2 moles of oxide were produced by 3 moles of O₂
I made 3 moles of oxide, so I used (3 .3) / 2 = 4.5 moles of O₂
I get enough amount of oxgen, so the limiting reactant is the Al.
2 moles of oxide were produced by 4 moles of Al
So, 3 moles of oxide were produced by (3 . 4) / 2 = 6 moles of Al
If I use the reactants, I get the same value.
3 moles of oxygen needs 4 moles of Al to react
Then, 4.5 moles of oxygen must need (4.5 . 4) /3 = 6 moles of Al
Answer:
There will react 6.00 moles Al and 4.50 moles O2 to produce 3.00 moles Al2O3 (option C)
Explanation:
Step 1: Data given
Number of moles O2 = 4.50 moles
Moles of Al2O3 = 3.00 moles
Step 2: The balanced equation
4Al(s) + 3O2(g) → 2Al2O3(s)
Step 3: Calculate moles of Al
For 3.00 moles Al2O3 produced, we need 2*3.00 = 6.00 moles Al
There will react 6.00 moles Al and 4.50 moles O2 to produce 3.00 moles Al2O3 (option C)
