Answer:
The vertical drop of the arrow is 1.225 m.
Explanation:
Given:
An arrow is shot horizontally at a speed of 60 m/s towards a target 30m away.
Now, to find the vertical drop of the arrow.
As, the arrow is shot horizontally so we take the horizontal component of velocity.
So, we put formula to solve it:
[tex]s=30.[/tex]
[tex]v=60.[/tex]
[tex]t=\frac{s}{v}[/tex]
[tex]t=\frac{30}{60}[/tex]
[tex]t=0.5\ s.[/tex]
Now, to get the vertical drop of the arrow we put formula:
[tex]s=\frac{1}{2} gt^2[/tex]
( As, we take [tex]g=9.8[/tex] )
[tex]s=\frac{1}{2}\times 9.8\times 0.5^2[/tex]
[tex]s=0.5\times 9.8\times 0.25[/tex]
[tex]s=1.225\ m.[/tex]
Therefore, the vertical drop of the arrow is 1.225 m.
