Answer and Explanation:
As we know that Polarity depends upon the electronegativity
as the F is highly electro negative so CBr2F2 is more polar.
Thus, the follwoing statements are true out of given statements
For more clarity and to have proper understanding, I have attached a file, please refer to the attached file to know the answer clearly.
Phosphine [tex](\rm PH_{3})[/tex] is less polar than ammonia [tex]\rm (NH_{3})[/tex] and Dichlorodifluoromethane [tex]\rm (CCl_{2}F_{2})[/tex] is less polar than Dibromodifluoromethane [tex]\rm (CBr_{2}F_{2})[/tex].
Polarity is the state of the atom or molecule possessing electric charges, with the formation of the electric dipole moment. They contain at least one polar bond.
The polarity of the atom or the molecule depends on the electronegativity and the electronegativity affects the electron distribution.
The fluorine atom in the Dibromodifluoromethane is highly electronegative and hence the Dibromodifluoromethane is more polar. Similarly, nitrogen is more electronegative than phosphorous and hence ammonia is more polar than Phosphine.
Therefore, polarity depends on electronegativity.
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