Answer:
8000 acres
Explanation:
Let x represent the total acres of land owned by the farmer, i.e. x = total acres of land
Given that 90% of the total acres of land was cleared, we can state this as 90% of x = 0.9x
Therefore, land cleared for farming = 0.9x
Also, given that 40% of the land cleared was planted with Soybeans, we can represent this as 40% of 0.9x = 40/100(0.9x) = (40*0.9x)/100 = 36x/100 = 0.36x
Land cleared that was planted with Soybean = 0.36x
50% of the land cleared that was planted with wheat = 50% of 0.9x = 0.45x
If Soybean = 0.36x, wheat = 0.45x, and corn is said to be 720, land cleared (0.9x) by the farmer can be represented below as:
0.36x + 0.45x + 720 = 0.9x
We can solve to find the value of x, which represents the total acres owned by the farmer.
We have, 0.81x + 720 = 0.9x
0.81x – 0.9x = – 720
– 0.09x = – 720
x = 8000
Total acres owned owned by the farmer is 8000 acres.
Answer: The total amount of land was 8000 acres
Explanation:
* Let's depict the total amount of the farmer's land for "m".
* 90% of the total land (m) was cleared for farming
i.e farming will be done on 90/100 × m = 9m/10 land
* Of the cleared land (9m/10 land), 50% was planted with wheat
i.e 50/100 × 9m/10 = 9m/20
* Of the cleared land (9m/10 land), 40% was planted with soyabeans
i.e 40/100 × 9m/10 = 9m/25
* Of the cleared land (9m/10 land), the remaining 10% or 720 acres (according to the information in the question) was planted with corn
i.e 10/100× 9m/10 = 9m/100
Hence, 9m/100 = 720 acres
Cross multiplying, 9m = 72000
m= 72000/9
m = 8000 acres
Therefore, the total amount of land the farmer had initially was 8000 acres
