Answer:
The average force is 28797.95 N.
Explanation:
Given that,
Mass of bullet = 7.80 g
Speed = 570 m/s
Distance = 4.40 cm
Suppose Use work and energy considerations to find the average force that stops the bullet.
We need to calculate the average force
Using work energy theorem
[tex]W=\Delta K.E[/tex]
[tex]F\cdot s=\dfrac{1}{2}mv^2[/tex]
Put the value into the formula
[tex]F\times 4.40\times10^{-2}=\dfrac{1}{2}\times7.80\times10^{-3}\times(570)^2[/tex]
[tex]F=\dfrac{\dfrac{1}{2}\times7.80\times10^{-3}\times(570)^2}{4.40\times10^{-2}}[/tex]
[tex]F=28797.95\ N[/tex]
Hence, The average force is 28797.95 N.
