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a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0 degree angle , against a 14.2 N friction force . find the work done by the friction force

Respuesta :

oladayoademosu

Answer:

a. -191.7 J

Explanation:

The work done by a force is given by W = Fdcosθ where F = force applied and d = distance moved and θ is the angle between the force and distance moved.

Here, F = frictional force = 14.2 N

d = distance = 13.5 m

and θ = 180° since the direction of the frictional force and distance are opposite.

So, W = Fdcosθ = 14.2 × 13.5cos180° = -191.7 J

alyssajwilliams

Answer:

152.54 J

Explanation:

W = | Fd | cos( theta)

W = | (19.7)(13.5) | cos(55)

W = 152.54 J