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Ask Your Teacher A coil has an inductance of 3.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.200 s. Find the magnitude of the average induced emf in the coil during this time interval.

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Answer:

Magnitude of the average induced emf in the coil [tex]= 0.0195[/tex] Volts

Explanation:

Induced emf in a coil with current flowing through it is can be calculated using the relation given below

[tex]emf = -L\frac{dI}{dt}[/tex] ------------ Equation (1)

Where "L" represents the inductance in H

dI represents the change in current in Ampere

and dt represents the change in time or time period for which the current is flowing in seconds

Given

[tex]L = 3.00[/tex] mH  [tex]= 3 * 10^ {-3}[/tex] H

[tex]I_0 = 0.200[/tex] Ampere

[tex]I_t = 1.50[/tex] Ampere

[tex]t = 0.200[/tex] seconds

Substituting the given values in equation (1) we get -

[tex]emf = - (3 * 10^{-3}) * \frac{1.500 - 0.200}{0.200} \\emf = 0.0195[/tex]

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